A Rectangular field 750m long and 450m broad has in the middle of it , road 5m wide running at right angles to each other , one long the length and the other along the breadth . Find the area of the path

the area of the path that is running along the breath is= 450*5=2250 m^2

the area of the path that is running along the length is= 750*5=3750 m^2
but as the two roads cross each other in the middle if we just sum the two areas it would over-estimate the crossing area.
so to negate the over-estimated region we have to deduct area of=5*5=25 m^2 from total.
total area=3750+2250-25=5975 m^2

Thankyou very much

The area of a small rectangular plot is 84 meter square.if the difference between its length and the breadth is 5m.find its perimeters?

area of a rectangular field is 450m2 the breadth of the field is 15 metre what is the ratio of length and area of the rectangular field?

Verma

To find the area of the path in the middle of the rectangular field, we need to subtract the area of the rectangle without the path from the area of the rectangle with the path.

1. Calculate the area of the entire rectangular field:
Area = Length * Breadth
= 750m * 450m
= 337,500 square meters

2. Calculate the area of each road:
Since there are two roads, we need to calculate the area of each road separately.

Area of the road along the length:
Width = 5m
Length = 750m
Area = Length * Width
= 750m * 5m
= 3,750 square meters

Area of the road along the breadth:
Width = 5m
Length = 450m
Area = Length * Width
= 450m * 5m
= 2,250 square meters

3. Calculate the total area of the path:
Total Area of the path = Area of the road along the length + Area of the road along the breadth
= 3,750 square meters + 2,250 square meters
= 6,000 square meters

4. Calculate the area of the field with the path:
Area of the field with path = Area of the rectangular field - Total Area of the path
= 337,500 square meters - 6,000 square meters
= 331,500 square meters

Therefore, the area of the path in the middle of the rectangular field is 6,000 square meters.