If 15gram of potassium trioxochlorate V is heated in the presence of MnO2.What is the mass of chloride produce?
To determine the mass of chloride produced when 15 grams of potassium trioxochlorate V (KClO3) is heated in the presence of MnO2, we need to consider the chemical reaction that occurs.
The balanced chemical equation for the decomposition of KClO3 is:
2KClO3(s) → 2KCl(s) + 3O2(g)
From the equation, we can see that for every 2 moles of KClO3 decomposed, 2 moles of KCl are produced. Since we know the molar mass of KClO3 (122.55 g/mol), we can determine the number of moles of KClO3 present.
Number of moles of KClO3 = mass of KClO3 / molar mass of KClO3
= 15 g / 122.55 g/mol
Next, we need to determine the number of moles of KCl produced. According to the balanced chemical equation, the molar ratio of KCl to KClO3 is 2:2 (1:1). Therefore, the number of moles of KCl will be the same as the number of moles of KClO3.
Number of moles of KCl = number of moles of KClO3
Finally, to calculate the mass of chloride (Cl) produced, we multiply the number of moles of KCl by the molar mass of KCl.
Mass of chloride produced = number of moles of KCl × molar mass of KCl
The molar mass of KCl is approximately 74.55 g/mol.
Now, let's calculate the mass of chloride produced:
Number of moles of KClO3 = 15 g / 122.55 g/mol
Number of moles of KCl = Number of moles of KClO3
Mass of chloride produced = Number of moles of KCl × molar mass of KCl