Barry is 8 years older than his sister. In 3 years, he will be twice as old as she will be then. How old is each now?
Please show work!
I don't understand.
B = S + 8
B + 3 = 2(S+3)
Substitute S + 8 for B.
S + 8 + 3 = 2(S+3)
S + 11 = 2S + 3
can you finish from here?
I really need help.
yes thanks
S-S+11=2S-S+3
11=S+3
11-3=S
8=S
Therefore
16=S+8
Matt is 24 years older than his son Liam, in two years Liam will be half of Matts age. How old is Liam now?
To solve this problem, we can use algebraic equations. Let's assign variables to the unknown ages. Let's say Barry's age is B and his sister's age is S.
From the information given, we can establish two equations:
1) Barry is 8 years older than his sister: B = S + 8
2) In 3 years, Barry will be twice as old as his sister will be then: B + 3 = 2(S + 3)
To solve these equations, we can use the method of substitution. We substitute the value of B from the first equation into the second equation:
(S + 8) + 3 = 2(S + 3)
S + 11 = 2S + 6
Next, we can solve for S:
S - 2S = 6 - 11
-S = -5
S = 5
Now that we know S = 5, we can substitute this value back into the first equation to find B:
B = S + 8
B = 5 + 8
B = 13
Therefore, currently, Barry is 13 years old, and his sister is 5 years old.