The hieght of women are approximately normally distributed with a mean of 65.4 inches and a standard deviation of 2.5 inches. What percent of these women would be over 70 inches or more?

70-64.5/2.5 = 2.2 Is this correct?
How would I determine the hieghts of the shortest 8% of the women?

2.2 is the z-score. YOu have to use a z-table to find the percent. You will want to look to the right of 2.2 to find the area which = the %

You will be looking at an area of .08 in the lower tail. You would have to find the z-score associated with it.
Use the z-score times the standard deviation ...