the primeter of a rectangle is 24ft. the length is 2 ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be the length and y be the width.
Is the answer for the lenght 16ft
and 8ft for the width?
No. Remember there are four sides to a rectangle. Also 16 is not 2 feet longer than the width.
Please try again.
okay 14ft for length and 10 for the width.
14 - 10 = 4
Your perimeter is 48 feet long.
P = 2L + 2W
24 = 2(W + 2) + 2W
I am getting lost here. I came up with 8 ft for the length and 4 ft for the width. I hope this is right.
But the length is only 2 feet longer than the width.
24 = 2(W + 2) + 2W
24 = 4W + 4
20 = 4W
5 = W
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5 + 2 = 7
Length = 7
Let's see if that produces a perimeter of 24
5 + 5 + 7 + 7 = 24