Find the coordinates of the point of intersection of the plane 2x+y-3z+6=0 on the y-axis
To find the coordinates of the point of intersection of the plane with the y-axis, we need to substitute x and z with 0 in the equation of the plane and solve for y.
Given the equation of the plane: 2x + y - 3z + 6 = 0
Substitute x = 0 and z = 0:
2(0) + y - 3(0) + 6 = 0
y + 6 = 0
y = -6
Therefore, the point of intersection of the plane with the y-axis has coordinates (0, -6, 0).