If you have 1.90 mol of H_2 , how many grams of NH_3 can be produced?
To determine the grams of NH3 that can be produced from 1.90 mol of H2, you need to use the balanced chemical equation for the reaction between H2 and NH3.
The balanced equation for the reaction is:
3H2 + N2 -> 2NH3
From the equation, you can see that 3 moles of H2 react to form 2 moles of NH3. Therefore, you can use a ratio to convert moles of H2 to moles of NH3.
Ratio: 3 mol H2 : 2 mol NH3
To calculate the moles of NH3, use the following proportion:
(1.90 mol H2) x (2 mol NH3 / 3 mol H2) = 1.26 mol NH3
Now, to find the grams of NH3 produced, you need to use the molar mass of NH3, which is approximately 17.03 g/mol.
To calculate the grams of NH3, use the following equation:
(1.26 mol NH3) x (17.03 g NH3 / 1 mol NH3) = 21.46 g NH3
Therefore, 1.90 mol of H2 can produce approximately 21.46 g of NH3.