a 135-g sample of sea water is evaporated to dryness, leaving 4.73 g of solid residue (the salts formerly dissolved in the seawater). calculate the mass percent of solute present in the original sea water.

please help I need to pass this test. thank you thank you forever!!!!!

To calculate the mass percent of solute in the original sea water, you need to divide the mass of the solute by the mass of the original sample and multiply by 100.

Step 1: Calculate the mass of the solute:
Mass of the solid residue = 4.73 g

Step 2: Calculate the mass of the original sample:
Mass of the original sample = 135 g

Step 3: Calculate the mass percent:
Mass percent = (mass of solute / mass of original sample) * 100

Mass percent = (4.73 g / 135 g) * 100

Mass percent ≈ 3.50%

Therefore, the mass percent of solute present in the original sea water is approximately 3.50%.

To calculate the mass percent of solute in the original sea water, you'll need to determine the mass of the solute and the mass of the original sea water.

Given:
Mass of the solid residue (solute) = 4.73 g
Mass of the original sea water = 135 g

To find the mass percent of solute, you can use the following formula:

Mass Percent of Solute = (Mass of Solute / Mass of Original Solution) * 100

Now let's plug in the values:

Mass Percent of Solute = (4.73 g / 135 g) * 100

Calculating this equation, we can determine the mass percent of the solute in the original sea water.

Mass Percent of Solute ≈ 3.5%

Therefore, the mass percent of the solute present in the original sea water is approximately 3.5%.

thanks (:

Hint:

%solute = (mass solute/mass sample)*100 = ?