Suppose a population of 160 crickets doubles in size every month. The function gives the population after x months. How many crickets will there be after 2 years?
(1 point)2,684,354,560 crickets
640 crickets
7,680 crickets
655,360 crickets
I have no idea
B
A
D
B
C
" I'M THE ANSWER MAN DO YOU KNOW THE ANSWER MAN "
the answer would be 2,684,354,569 crickets
2 years is 24 six-month periods, so the population doubles 4 times = 2^24 times the original population.
2^24 ~= 10^7
160 ~= 10^2
so the result will be somewhere around 10^9
Looks like the 1st choice.
thank you steve you've saved my life
Actually @Diamond Chic, Steve is correct!
bffr
I'm sorry, but I'm not sure what "bffr" means. Can you please provide more context or information so I can better assist you?
To find the number of crickets after 2 years, we need to determine the value of the function f(x) at x=24 (since there are 12 months in a year and we want to find the population after 2 years).
The function given is that the population doubles every month, so we can write the function as:
f(x) = 160 * 2^x
Plugging in x=24 into the function, we have:
f(24) = 160 * 2^24
Calculating this, we get:
f(24) = 160 * 16,777,216
f(24) = 2,684,354,560
Therefore, after 2 years, there will be 2,684,354,560 crickets.
So, the correct answer is:
(1 point) 2,684,354,560 crickets.
this is so wrong
10^9=1000000000