Same kind of problem. How to rearrange to put an equation in quadratic form.
Example I'm given is
49.7= 2x^2 / (1.00-x)(2.00-x)
which should come out to .920x^2 -3.0x + 2.0
but I can't figure out exactly how to get to there, especially how to get the x squared number.
For denominator you have to multiply the two binomials.
(1-x)(2-x)
Multiply 1 times the terms in the second binomial then multiply -x times the terms in the second binomial.
2 -x -2x +x^2
simplify to 2 -3x + x^2
rewrite in descending order to get
x^2 -3x + 2
Mulitply that by 49.7 and that answer will be equal to 2x^2
Subtract 2x^2 from both sides to get your answer.
I did this assuming that the (1.00-x)(2.00-x) is all under the division sign and the whole thing is in the denominator.