Open Question: Find the electric field between the plates of a capacitor given the following:?

(1) C= 10pF (2) the capacitor is connected to a 25 V battery (3) there is a vacuum between the capacitor plates (4) plate separation is 2 mm

You don't need all of that information.

The E field is 25V/0.002m = 12,500 V/m
or Newtons/Coulomb

What is C =10 pF ?

To find the electric field between the plates of a capacitor, you can utilize the formula:

E = V/d

Where:
E is the electric field in between the plates,
V is the voltage across the capacitor plates, and
d is the distance between the plates.

In this case, the given information is as follows:
(1) C = 10 pF (picoFarads) - This represents the capacitance of the capacitor.
(2) The capacitor is connected to a 25 V battery - This is the voltage across the capacitor plates.
(3) There is a vacuum between the capacitor plates - This indicates that the medium between the plates has a permittivity of ε₀, which is approximately equal to 8.85 x 10⁻¹² F/m.
(4) The plate separation is 2 mm - This is the distance between the plates.

First, let's convert the capacitance from picoFarads to Farads:
10 pF = 10 x 10⁻¹² F

Now, we have all the values we need to calculate the electric field.

Substituting these values into the formula, we get:
E = (25 V) / (2 x 10⁻³ m)

Simplifying further, we have:
E = 12.5 x 10³ V/m

Therefore, the electric field between the plates of the capacitor is 12.5 x 10³ V/m.