A distribution of weights is symmetric about its median. The lower quartile of the weights is 90 pounds and the median is 120 pounds. Find the interquartile range of the distribution.
If weights are symmetric about the median then is you have 90 lbs at the lower quartile, you should have 150 at the upper quartile.
Subtract the two numbers to get the interquartile range.
i did't get it even i got the wright answer , how do u calculated upper quartile ?? on hit and trial basis??
The upper quartile is the 75th percentile.
150
To find the interquartile range of the distribution, we first need to determine the upper quartile.
Given that the distribution of weights is symmetric about its median, we know that the lower quartile is located at the same distance below the median as the upper quartile is located above the median.
Since the median is 120 pounds and the lower quartile is 90 pounds, the upper quartile is 120 + (120 - 90) = 150 pounds.
The interquartile range is then calculated as the difference between the upper quartile and the lower quartile: 150 - 90 = 60 pounds.
Therefore, the interquartile range of the distribution is 60 pounds.