If a plate is dropped and comes in contact with a hard floor vs a playe coming in contact with a carpet, which has the greater impulse?

Impact is change momentum, or delta Velocity*mass. Don't they have the same change of velocity, and the same mass?

Denke.

Yeah, so therefor it is the same impulse?

but J = FT
The force is the same but the T interaction is different? or something?

If time of contact is different, then the forces are different. But implulse is the same.

thanks!

A small first-aid kit is dropped by a rock climber who is descending steadily at 0.5 m/s.

(a) After 2.6 s, what is the velocity of the first-aid kit?

To determine which scenario has the greater impulse, we need to understand what impulse is. Impulse is the change in momentum of an object and is given by the equation:

Impulse = Force × Change in Time

The momentum of an object is defined as the product of its mass and velocity:

Momentum = Mass × Velocity

In this case, since the plate is dropped, we can assume that its mass remains constant. Therefore, the plate's impulse mainly depends on the force exerted and the change in time, which is directly related to the plate's final velocity.

When a plate is dropped and comes in contact with a hard floor, it experiences a high force of impact due to the rigid and unyielding nature of the floor. This force acts over a very short period of time, resulting in a significant change in momentum and thus a large impulse.

On the other hand, when a plate comes in contact with a carpet, the carpet provides a more cushioned and soft surface. As a result, the force of impact is reduced, and the time over which the force is applied is longer. This leads to a smaller change in momentum and a relatively smaller impulse.

Therefore, in general, a plate dropped and coming in contact with a hard floor will have a greater impulse compared to when it comes in contact with a carpet.