Calculate the molarity of Formic acid in a solution containing 44g of Formica acid in 470 g of nitrobenzene. The molar mass of Formica acid is 36g/mol

2.6m

To calculate the molarity of Formic acid, we need to determine the number of moles of Formic acid and the volume of the solution.

1. Calculate the number of moles of Formic acid:
Number of moles = mass / molar mass
Number of moles = 44g / 36g/mol
Number of moles = 1.22 mol

2. Calculate the volume of the solution:
Volume of solution = 470g

3. Convert the volume of the solution to liters:
Volume of solution = 470g / 1g/mL = 470 mL
Volume of solution = 470 mL / 1000 mL/L = 0.47 L

4. Now, calculate the molarity of the Formic acid:
Molarity (M) = moles / volume
Molarity (M) = 1.22 mol / 0.47 L
Molarity (M) ≈ 2.60 M

Therefore, the molarity of Formic acid in the solution is approximately 2.60 M.

To calculate the molarity of Formic acid in the given solution, we need to first calculate the number of moles of Formic acid present in the solution, and then divide it by the volume of that solution.

Step 1: Calculate the number of moles of Formic acid.
Number of moles = Mass of Formic acid / Molar mass of Formic acid

Given:
Mass of Formic acid = 44g
Molar mass of Formic acid = 36g/mol

Number of moles = 44g / 36g/mol

Simplify:
Number of moles = 1.22 mol (rounded to two decimal places)

Step 2: Calculate the volume of the solution.
Volume of the solution is not given directly. However, we can use the total mass and density of nitrobenzene to calculate it.

Given:
Mass of nitrobenzene = 470g
Density of nitrobenzene = 1.20 g/mL (or 1200 g/L)

Volume of the solution = Mass of nitrobenzene / Density of nitrobenzene

Substituting the given values:
Volume of the solution = 470g / 1200 g/L

Simplify:
Volume of the solution = 0.392 L (rounded to three decimal places)

Step 3: Calculate the molarity.
Molarity (M) = Number of moles / Volume of the solution

Substituting the calculated values:
Molarity (M) = 1.22 mol / 0.392 L

Simplify:
Molarity (M) = 3.11 M (rounded to two decimal places)

Therefore, the molarity of Formic acid in the given solution is 3.11 M.