What is the percent by mass of glucose in a solution containing .15 mol of glucose dissolved in 410 g acetic acid? The molar mass of glucose is 180g/mol.
To find the percent by mass of glucose in the solution, you need to determine the mass of glucose and the total mass of the solution.
First, calculate the mass of glucose:
Mass of glucose = Number of moles of glucose × Molar mass of glucose
Mass of glucose = 0.15 mol × 180 g/mol
Mass of glucose = 27 g
Next, determine the total mass of the solution:
Total mass of the solution = Mass of glucose + Mass of acetic acid
Total mass of the solution = 27 g + 410 g
Total mass of the solution = 437 g
Finally, calculate the percent by mass of glucose in the solution:
Percent by mass of glucose = (Mass of glucose / Total mass of the solution) × 100
Percent by mass of glucose = (27 g / 437 g) × 100
Percent by mass of glucose ≈ 6.18%
Therefore, the percent by mass of glucose in the solution is approximately 6.18%.