blue-green light has a frequency of about 6X10 to the fourth Hz. use the relationship c=fl to find the wavelength of this light in air. how does this wavelength compare with the size of the atom, which is about 10 is to ten?
where did you get the numbers on the frequency? It is grossly in error.
To find the wavelength of the blue-green light in air, we can use the relationship between the speed of light (c), frequency (f), and wavelength (λ), which is given by the equation c = fλ.
Given frequency (f) = 6 × 10^4 Hz, and the speed of light in a vacuum (c) is approximately 3 × 10^8 m/s or 3 × 10^17 nm/s, we can substitute these values into the equation to solve for wavelength (λ).
c = fλ
λ = c / f
Substituting the values, we get:
λ = (3 × 10^17 nm/s) / (6 × 10^4 Hz)
Now, let's calculate the wavelength:
λ = 5 × 10^12 nm
The resulting wavelength of the blue-green light in air is approximately 5 × 10^12 nm.
Comparing this wavelength to the size of an atom, which is about 10 to the power of -10 meters (10^-10 m), we can convert the size to nanometers:
Size of atom = 10^-10 m * (10^9 nm/1 m) = 0.1 nm
Therefore, the size of an atom is approximately 0.1 nm.
By comparing the wavelength of blue-green light (5 × 10^12 nm) to the size of an atom (0.1 nm), we can see that the wavelength of the light is significantly larger than the size of an atom.