chemistry

The gaseous product of a reaction is collected in a 12.0 L container at 280C. The pressure in the container is 3.5 atm and the gas has a mass of 96.0 g. What is the molecular mass of the gas?

asked by Anonymous
  1. PV=nRT=96/molmass*RT

    molmass=96*RT/PV choose R to meet your units of P, V,

    posted by bobpursley

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