What is the value of n so that the expression x² + 11x + n is a perfect square trinomial?

A.11
B.25
C.30.25
D.36

I think it is C...?

1. 30.25

2. X= -1
3. No solution
4. 8 in
Your welcome and you got this

I believe it is C!! good job dear!

I completely agree with friend. That is not nice of you and the fact that he just wants help, dont post anything if your not gonna help him.

Well, the value of n that would make the expression a perfect square trinomial is 36. So, the correct answer is D, just like my optimistic outlook on life - always looking for the perfect square!

To determine the value of n, we need to consider the expression x² + 11x + n.

A perfect square trinomial has the form (ax + b)², where a is the coefficient of the x term and b is half the coefficient of the x term.

In our case, the coefficient of the x term is 11. Therefore, half of 11 is 11/2 = 5.5.

For the expression x² + 11x + n to be a perfect square trinomial, the value of n should be the square of half the coefficient of the x term. In this case, it should be (11/2)² = 30.25.

Therefore, the correct answer is C. 30.25.

don't just "think it is c), be absolutely sure it is c)