Analytical Chemistry

A 22.617 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 70.407 g of water. A 10.883 g aliquot of this solution is then titrated with 0.1072 M HCl. It required 29.32 mL of the HCl solution to reach the methyl red endpoint. Calculate the weight percent NH3 in the aqueous waste.

wt% NH3 = ??

Hint: The titration equation shows one mole of HCl reacts with one mole of NH3:

HCl + NH3 <---> NH4^+ + Cl^-

Haven't covered this topic in class yet. How to solve??

  1. 👍 0
  2. 👎 0
  3. 👁 1,034
  1. This is how I would go about solving this problem.

    moles of NH3 in sample= 0.1072M * 29.32 x 10^-3L=3.14 x 10^-3 moles of NH3.

    Remember, the mole ratios are equal since it takes one mole of NH3 to react with one mole of HCl.

    3.14 x 10^-3 moles of NH3*(17.031g NH3/ 1mole)= mass of NH3

    (mass of NH3/mass of aliquot sample)= ratio of NH3 in sample after it was diluted

    ratio of NH3 in sample after it was diluted* total weight after dilution= total mass of of NH3 in sample

    (total mass of of NH3 in sample/22.617 g sample of aqueous waste)*100= wt% NH3

    *****I left a note for you in one of your other posts about a correction.

    1. 👍 2
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. Math I need help ASAP!

    1. which of the following is true of a random sample? a. it is the only way to sample a population. b. each member of the sample is a volunteer. c. it is always the easiest way to sample a population. d. each member of the

  2. Chemistry

    a) Ammonia, an important source of fixed nitrogen that can be metabolized by plants, is produced using the Haber process in which nitrogen and hydrogen combine. N2(g) + 3H2(g) → 2NH3(g) How many grams of nitrogen are needed to

  3. chemistry

    The quantity of antimony in a sample can be determined by an oxidation-reduction titration with an oxidizing agent. A 6.35-g sample of stibnite, an ore of antimony, is dissolved in hot, concentrated HCl(aq) and passed over a

  4. statistics

    A sample of 100 iron bars is said to be drawn from a large number of bars. Whose lengths are normally distributed with mean 4 feet and S.D 0.6ft. If the sample mean is 4.2 ft, can the sample be regarded as a truly random sample?

  1. statistics

    a manufacturer of detergent claims that the contents of the boxes in the market weigh on average at least 16 oz.. the distribution of weights is known to be normal with a standard deviation of 0.4 oz. to test the claim of the

  2. Chemistry

    Ammonia has the formula NH3. Household ammonia is a dilute aqueous solution of NH3 . Aqueous ammonia is a base that can neutralize acids. If 18.4mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia

  3. statistics

    A manufacturer of cell phones has decided that an assembly line will be considered to be operating satisfactorily if less than 0.02% of the phones produced per day are defective. To check the quality of a day's production, the

  4. chemistry

    Can someone give me some directions as to how to reach the answer for this problem: A 0.608g sample of fertilizer contained nitrogen as ammonium sulfate, (NH4)2 SO4(s)+2NaOH(aq)-->Na2SO4(aq)+ 2H2O(l)+2NH3(g) The ammonia was

  1. Science

    A scientist observed two rock samples. Sample A was found in the bottom of a dried-up lake and contained fossils. Sample B was found near a volcano and was glassy in appearance. Which statement is MOST LIKELY correct? A. Sample A

  2. chemistry

    A 23.596 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 79.504 g of water. A 13.803 g aliquot of this solution is then titrated with 0.1098 M HCl. It required 29.02 ml of

  3. marketing

    Binomial probability distributions are used in business, science, engineering, and other fields. Suppose you work for a marketing agency and have to create a television ad for Brand A toothpaste. The toothpaste manufacturer claims

  4. Chemistry

    a 5.000ml aqueous sample containing hydrogen peroxide as diluted to 25ml and analyzed by titration with permanganate. 2MnO4- + 5H2O + 6H+ --> 5O2 + 2Mn^2+ + 8H2O The sample required 42.8 mL of 0.0175 M permangante to reach the end

You can view more similar questions or ask a new question.