A bird stands on a bare power line carrying 2500 amps of current. 600 meters of this wire has a resistance of .009 ohms.
If the bird's feet are 3 cm apart, what is the voltage difference between the bird's feet?
To find the voltage difference between the bird's feet, we can use Ohm's Law, which states that voltage (V) is equal to the product of current (I) and resistance (R):
V = I * R
First, we need to convert the distance between the bird's feet from centimeters to meters:
3 cm = 0.03 meters
Now, let's substitute the given values into the formula:
V = 2500 amps * 0.009 ohms
V = 22.5 volts
Therefore, the voltage difference between the bird's feet is 22.5 volts.
To find the voltage difference between the bird's feet, we can use Ohm's Law, which states that voltage (V) is equal to the product of current (I) and resistance (R).
In this case, the current flowing through the wire is 2500 amps, and the resistance of the wire is 0.009 ohms. Therefore, the voltage difference can be calculated as:
V = I * R
V = 2500 amps * 0.009 ohms
V ≈ 22.5 volts
So, the voltage difference between the bird's feet is approximately 22.5 volts.