In the following reaction, how many liters of oxygen will react with 270 liters of ethene (C2H4) at STP?
C2H4(g) + 3O2(g) ---> 2CO2(g) + 2H2O(g)
The volume of one mole of gas at STP is 22.4 liters.
In the following reaction, how many liters of oxygen will react with 270 liters of ethene (C2H4) at STP?
C2H4(g) + 3O2(g) 2CO2(g) + 2H2O(g)
The volume of one mole of gas at STP is 22.4 liters
135 liters
To determine the number of liters of oxygen required to react with 270 liters of ethene (C2H4) at STP, we need to use the stoichiometry of the balanced chemical equation.
According to the balanced equation, the stoichiometric ratio between C2H4 and O2 is 1:3. This means that for every 1 mole of C2H4, 3 moles of O2 are required.
To convert the given volume of ethene (270 liters) to moles, we divide by the molar volume of a gas at STP, which is 22.4 liters/mol:
270 liters C2H4 * (1 mol C2H4 / 22.4 liters C2H4) = 12.05 moles C2H4
Now, we can calculate the number of moles of O2 needed using the stoichiometric ratio:
12.05 moles C2H4 * (3 moles O2 / 1 mole C2H4) = 36.15 moles O2
Finally, we can convert moles of O2 to volume at STP using the molar volume:
36.15 moles O2 * (22.4 liters O2 / 1 mol O2) = 809.36 liters O2
Therefore, 809.36 liters of oxygen will react with 270 liters of ethene (C2H4) at STP.