Calculate the pH of a .50 M solution of NaCl.
Don't think that you can do that. pH should be neutral=7.
But if you must calculate it I would do this.
2H2O ==> H3O^+ + OH^-
(H3O^+))OH^-) = K\w = 1E-14
(x)(x) = 1E-14
x = sqrt(1E-14) = 1E-78
pH = 7
To calculate the pH of a solution, we need to determine if the solute dissociates or reacts with water to form any acidic or basic species. In the case of NaCl, it is a salt and completely dissociates into Na+ and Cl- ions in water.
Since neither the Na+ nor Cl- ions react with water to produce acidic or basic species, the solution does not have any H+ or OH- ions contributing to its acidity or basicity. Therefore, the pH of a .50 M solution of NaCl is neutral and equal to 7.
To confirm this, you can also calculate the concentration of H+ ions in the solution using the equation:
[H+] = 10^(-pH)
Substituting pH = 7 into the equation:
[H+] = 10^(-7) = 0.0000001 M
So, the concentration of H+ ions in the solution is very low, confirming its neutral pH value.