a 0.67 kg rubber ball has a speed of 2.2 m/s at point a and kinetic energy 7.1 J at point B find the total work done on the ball as it moves from a to b
Ek1 =0.5*0.67*(2.2)^2=1.62 J. @ point a.
Ek2 = 7.1 J. @ point b.
Work = The change in kinetic energy.
Work = Ek2 - Ek1 = 7.1 - 1.62 = 5.48 J.
To find the total work done on the ball as it moves from point A to point B, we can use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.
The initial kinetic energy of the ball at point A can be calculated using the formula:
Kinetic Energy (KE) = (1/2) * mass * velocity^2
KE at A = (1/2) * 0.67 kg * (2.2 m/s)^2
KE at A = (1/2) * 0.67 kg * 4.84 m^2/s^2
KE at A = 1.6242 J (rounded to four decimal places)
The change in kinetic energy from point A to point B is given as 7.1 J - 1.6242 J = 5.4758 J (rounded to four decimal places).
Therefore, the total work done on the ball as it moves from A to B is equal to the change in kinetic energy:
Work = Change in KE = 5.4758 J
So, the total work done on the ball is 5.4758 J.