a 0.67 kg rubber ball has a speed of 2.2 m/s at point a and kinetic energy 7.1 J at point B find the total work done on the ball as it moves from a to b
W=KE2-KE1=KE2 - mv²/2=
=7.14 - 0.67•2.2²/2 = 5.52 J
To find the total work done on the ball as it moves from point A to point B, we need to calculate the change in kinetic energy of the ball.
The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. So, the total work done can be expressed as:
Work = Change in Kinetic Energy
Given that the mass (m) of the rubber ball is 0.67 kg, we can calculate the initial kinetic energy (KEa) at point A using the formula:
KEa = (1/2) * m * v^2
where v is the speed of the ball at point A.
Substituting the given values, we have:
KEa = (1/2) * 0.67 kg * (2.2 m/s)^2 = 0.808 J
Next, we find the change in kinetic energy (ΔKE) between point A and point B:
ΔKE = KEb - KEa
Given that the kinetic energy (KEb) at point B is 7.1 J, we can substitute the values:
ΔKE = 7.1 J - 0.808 J = 6.292 J
Therefore, the total work done on the ball as it moves from point A to point B is 6.292 Joules.