When the concentration of CH3Br and NaOH are both 0.150M, the rate of the reaction is 0.0020M/S.
(a) What is the rate of the reaction if the concetration of CH3Br is doubled?
_______________M/s
(b) What is the rate of the reaction if the concentration of NaOH is halved?
_______________M/s
(c) What is the rate of the reaction if the concentrations of CH3Br and NaOH are both increased
by a factor of six?
_______________M/s
a) 0.004
b)0.001
c) ?
c) 0.0713
How did you get the answer for letter C
To answer these questions, we can use the rate equation for the reaction and apply the principles of stoichiometry. The rate equation is of the form: rate = k[CH3Br]^x[NaOH]^y, where k is the rate constant, [CH3Br] is the concentration of CH3Br, [NaOH] is the concentration of NaOH, and x and y are the orders of the reaction with respect to CH3Br and NaOH, respectively.
Given that the concentrations of CH3Br and NaOH are both 0.150M and the rate of the reaction is 0.0020M/s, we can substitute these values into the rate equation:
0.0020 M/s = k * (0.150 M)^x * (0.150 M)^y
We can simplify this expression by using exponential properties:
0.0020 M/s = k * (0.150 M)^(x+y)
Now, let's go through each question and determine the effect of the changes in concentration on the rate of the reaction:
(a) If the concentration of CH3Br is doubled while the concentration of NaOH remains constant, the new concentration of CH3Br would be 2 * 0.150 M = 0.300 M. To find the new rate of the reaction, we can substitute this value into the rate equation:
new rate = k * (0.300 M)^(x+y)
(b) If the concentration of NaOH is halved while the concentration of CH3Br remains constant, the new concentration of NaOH would be 0.150 M / 2 = 0.075 M. To find the new rate of the reaction, we can substitute this value into the rate equation:
new rate = k * (0.150 M)^(x+y) * (0.075 M)^y
(c) If the concentrations of both CH3Br and NaOH are increased by a factor of six, the new concentrations would be 6 * 0.150 M = 0.900 M. To find the new rate of the reaction, we can substitute this value into the rate equation:
new rate = k * (0.900 M)^(x+y)
To calculate the specific rates, we need to know the values of x and y, which can be determined experimentally or given in the problem. Without this information, we cannot calculate the numerical values for the rate.