A 9V battery has an electric potential difference of 9V between the positive and negative terminals. How much kinetic energy in J would an electron gain if it moved from the negative terminal to the positive one?
To calculate the kinetic energy gained by an electron when it moves from the negative terminal to the positive terminal of a 9V battery, we need to consider the relationship between electric potential difference and kinetic energy.
The electric potential difference (V) is given in volts (V), and the kinetic energy (K) is given in joules (J). The formula to calculate the kinetic energy gained by the electron is:
K = q * V
Where:
- K is the kinetic energy gained
- q is the charge of the electron (1.6 x 10^(-19) coulombs)
- V is the electric potential difference (9V)
Now, let's plug in the values into the formula:
K = (1.6 x 10^(-19) C) * (9V)
Calculating this, we get:
K = 1.44 x 10^(-18) J
Therefore, the electron would gain approximately 1.44 x 10^(-18) joules of kinetic energy when it moves from the negative terminal to the positive terminal of the 9V battery.