two particles perform linear simple harmonic motionalongthe same path of length 2A and period T as shown in the graph below. the phase differe3nce between them is -------------

To determine the phase difference between two particles performing linear simple harmonic motion on the same path, you need to examine the graph of their motion. However, there is no graph provided in your question. Therefore, I'll explain the general method of finding the phase difference between two particles in simple harmonic motion.

1. Determine the equations of motion for both particles:
- Particle 1: x1 = A sin(ωt + φ1)
- Particle 2: x2 = A sin(ωt + φ2)

Here, x1 and x2 represent the displacements of particles 1 and 2 from their respective mean positions, ω is the angular frequency, t is time, and φ1 and φ2 are the phase constants.

2. Identify the key variables:
- Period (T): The time taken to complete one full cycle of oscillation.
- Amplitude (A): The maximum displacement from the mean position.

3. Calculate the angular frequency (ω):
ω = 2π / T

4. Find the time taken for one complete cycle (T):
Since both particles have the same period, T is equal for both particles.

5. Use the given information to find the phase difference (Δφ):
Δφ = φ2 - φ1

Please provide the graph or additional details if you want a specific calculation based on the given scenario.