What is the momentum of a 50 kg carton that slides at 2 m/s across an icy surface?

The sliding carton skids onto a rough surface and stops in 3 s. Calculate the force of friction it encounters.

Momentum = m*V = 50 * 2 = 100.

a = (V-Vo)/t = (0-2)/3 = -0.667 m/s^2.
Fk = m*a = 50 * (-0.667) = -33.3 N.

To find the momentum of the carton, we can use the formula:

Momentum = Mass * Velocity

Given that the mass of the carton is 50 kg and its velocity is 2 m/s, we can substitute these values in the formula:

Momentum = 50 kg * 2 m/s

Momentum = 100 kg·m/s

Therefore, the momentum of the carton is 100 kg·m/s.

To calculate the force of friction, we will use Newton's second law of motion:

Force = Mass * Acceleration

The carton comes to a stop, so its final velocity is 0 m/s. We can use the formula:

Acceleration = (Final Velocity - Initial Velocity) / Time

Given that the initial velocity is 2 m/s and the time taken to stop is 3 s, we can substitute these values in the formula:

Acceleration = (0 m/s - 2 m/s) / 3 s

Acceleration = (-2 m/s) / 3 s

Acceleration = -0.67 m/s^2

Now we can calculate the force of friction using the formula:

Force = 50 kg * (-0.67 m/s^2)

Force = -33.5 N

Therefore, the force of friction that the carton encounters is 33.5 N. The negative sign indicates that the friction is acting in the opposite direction to the motion of the carton.

To find the momentum of the 50 kg carton sliding at 2 m/s, we can use the formula:

Momentum = mass × velocity

So, the momentum of the carton is:

Momentum = 50 kg × 2 m/s
Momentum = 100 kg·m/s

To calculate the force of friction, we can use Newton's second law of motion, which states that force is equal to the change in momentum divided by the time over which the change occurs. In this case, the change in momentum is equal to the initial momentum (100 kg·m/s) because the carton comes to a stop, and the time is given as 3 seconds.

Force = Change in Momentum / Time

Force = (Final Momentum - Initial Momentum) / Time

Since the carton comes to a stop, the final momentum is zero. Therefore, the force of friction can be calculated as:

Force = (0 kg·m/s - 100 kg·m/s) / 3 s
Force = -100 kg·m/s / 3 s

The negative sign indicates that the force is acting in the opposite direction of motion (i.e., the frictional force is opposing the motion of the carton).

Evaluating the expression gives us:

Force ≈ -33.33 N

Therefore, the force of friction encountered by the carton is approximately 33.33 N.