In the reaction 2H2O2(aq)-->2H2O2 + O2 (g), There is intially 0.865 M H2O2. After 10.0 minutes, the molarity of H2O2 changes to 0.792 M. What is the rate of reaction in terms of H2O2?
To determine the rate of the reaction in terms of H2O2, we need to use the formula:
Rate = (change in concentration of H2O2) / (time)
Given that the initial concentration of H2O2 (H2O2 initial) is 0.865 M and the concentration of H2O2 after 10.0 minutes (H2O2 final) is 0.792 M, we can calculate the change in concentration of H2O2 as follows:
Change in concentration of H2O2 = H2O2 final - H2O2 initial
= 0.792 M - 0.865 M
= -0.073 M
Now, we can calculate the rate of reaction using the formula above:
Rate = (change in concentration of H2O2) / (time)
= (-0.073 M) / (10.0 minutes)
= -0.0073 M/min
Therefore, the rate of reaction in terms of H2O2 is -0.0073 M/min.
To determine the rate of reaction in terms of H2O2, we need to calculate the change in concentration of H2O2 over a given time interval. The rate of reaction is defined as the change in concentration per unit of time.
In this case, we are given the initial concentration of H2O2 (0.865 M) and the final concentration of H2O2 after 10.0 minutes (0.792 M).
The formula to calculate the rate of reaction is:
Rate = (Change in concentration of H2O2) / (Change in time)
Let's plug in the values we have:
Change in concentration of H2O2 = Final concentration - Initial concentration
= 0.792 M - 0.865 M
= -0.073 M
Change in time = Final time - Initial time
= 10.0 minutes - 0.0 minutes
= 10.0 minutes
Now we can calculate the rate of reaction:
Rate = (Change in concentration of H2O2) / (Change in time)
= (-0.073 M) / (10.0 minutes)
≈ -0.0073 M/min
Therefore, the rate of reaction in terms of H2O2 is approximately -0.0073 M/min.