What is the total pressure at the bottom of a lake at a depth of 38m?
Atmospheric pressure PLUS
(water density)*g*depth
= 1.01*10^5 + (10^3)*9.8*38
= (1.01 + 3.72)*10^5
= 4.73*10^5 Pascals
= 3.69 atmospheres
mm that answer is correct
To calculate the total pressure at the bottom of a lake at a given depth, we can use the concept of hydrostatic pressure. The hydrostatic pressure is the pressure exerted by a fluid at a specific depth due to the weight of the fluid above it.
The formula to calculate hydrostatic pressure is:
P = ρ * g * h
Where:
P is the hydrostatic pressure
ρ (rho) is the density of the fluid (water in this case)
g is the acceleration due to gravity (approximately 9.8 m/s^2)
h is the depth or height of the fluid column
In this case, the fluid is water, and we know the depth is 38m. The density of water is approximately 1000 kg/m^3.
Let's calculate:
P = 1000 kg/m^3 * 9.8 m/s^2 * 38 m
P ≈ 372,400 Pa (Pascal)
Therefore, the total pressure at the bottom of the lake at a depth of 38m is approximately 372,400 Pascal (Pa), or you can also say 372.4 kilopascals (kPa).