calculate the percentage of water in each of the following hydrates
SrCl2*6H2O
screw this
(6*molar mass H2O/molar mass SrCl2.6H2O)*100 = ?
To calculate the percentage of water in a hydrate, you need to determine the ratio between the molar mass of the water and the total molar mass of the hydrate.
To start, let's find the molar mass of water (H2O). The atomic mass of hydrogen (H) is approximately 1 gram/mole, and the atomic mass of oxygen (O) is approximately 16 grams/mole. Since there are two hydrogen atoms and one oxygen atom in water, the molar mass of water is:
Molar mass of water (H2O) = (2 * Atomic mass of hydrogen) + Atomic mass of oxygen
= (2 * 1 g/mole) + 16 g/mole
= 18 g/mole
Next, let's find the molar mass of the entire hydrate (SrCl2•6H2O). The molar mass of strontium chloride (SrCl2) can be calculated using the atomic masses of strontium (Sr) and chlorine (Cl). The atomic mass of strontium is approximately 88 grams/mole, and the atomic mass of chlorine is approximately 35.5 grams/mole. Since there are two chlorine atoms in strontium chloride, the molar mass of strontium chloride is:
Molar mass of strontium chloride (SrCl2) = Atomic mass of strontium + (2 * Atomic mass of chlorine)
= 88 g/mole + (2 * 35.5 g/mole)
= 88 g/mole + 71 g/mole
= 159 g/mole
Since there are six water molecules in the hydrate, we need to multiply the molar mass of water (18 g/mole) by 6:
Molar mass of water in the hydrate (6H2O) = 6 * 18 g/mole
= 108 g/mole
Finally, we can calculate the percentage of water in the hydrate by dividing the molar mass of water by the total molar mass of the hydrate:
Percentage of water = (Molar mass of water in the hydrate / Molar mass of the hydrate) * 100
= (108 g/mole / 159 g/mole) * 100
≈ 67.92%
Therefore, the percentage of water in the SrCl2•6H2O hydrate is approximately 67.92%.
is that dot between the compounds multiplication?
No.
CuSO4.5H2O means 1 mol CuSO4 + 5 mol H2O. The molar mass is
Cu + S + 4*O + 5*H2O = about 249.5
If we could put it in the right place on the computer it would be a period in the middle of the line. We can't do that with the computer so we write it as a period on the line. Some write it as CuSO4*5H2O but that DOES look like a multiplication.