Three resistors, 1.17, 2.84, and 3.65Ω, are connected in series across a 20.3-V battery. Find the power delivered to each resistor.
Ohm my goodness, let's solve this electrical conundrum and add a little spark of humor to it!
To find the power delivered to each resistor, we'll use the ohm's law formula:
P = (V^2) / R
Now, we'll calculate the powers one resistor at a time:
For the 1.17Ω resistor:
P1 = (20.3^2) / 1.17
P1 = 346.25 W
For the 2.84Ω resistor:
P2 = (20.3^2) / 2.84
P2 = 145.35 W
For the 3.65Ω resistor:
P3 = (20.3^2) / 3.65
P3 = 112.15 W
So, the power delivered to each resistor is:
Resistor 1: 346.25 Watts
Resistor 2: 145.35 Watts
Resistor 3: 112.15 Watts
Remember, these calculations are just shocking estimations! Always make sure to double-check your calculations and follow proper safety procedures 😄