an air bubble trapped in bread dough at room temperature (291k) has a volume of 1.0mL. The bread bake sin the oven at 623k(350C)
calculate the new volume of the air bubblr, using charles law( Volume divided by Temperature= K)
my answer is: 1.0/350C = 2.857....x10-03
this doesnt seem right...
V1/T1 = V2/T2
It doesn't seem right to me either. You haven't used the 291 at all AND you used 350 C without converting to Kelvin.
1/291 = V2/623
Solve for V2
You are on the right track, but there is a slight mistake in your calculation. To use Charles's Law, we need to convert the temperatures to the Kelvin scale.
Room temperature is 291 K, and the baking temperature in the oven is 623 K.
Using Charles's Law equation (V1/T1 = V2/T2), where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature:
V1 / T1 = V2 / T2
Substituting the given values:
1.0 mL / 291 K = V2 / 623 K
Now, to solve for V2, we can cross-multiply and divide:
V2 = (1.0 mL x 623 K) / 291 K
V2 ≈ 2.14 mL
So, the new volume of the trapped air bubble, when the bread is baked in the oven, is approximately 2.14 mL.
To calculate the new volume of the air bubble using Charles's law, we need to convert the temperatures to Kelvin because Charles's law uses the absolute temperature scale. To convert Celsius to Kelvin, we add 273.15 to the Celsius value.
Initial temperature (T₁) = 291 K
Final temperature (T₂) = 623 K
Now let's use Charles's law:
Volume/Temperature = K
Using the initial conditions:
1.0 mL / 291 K = K
Let's solve for K:
K = 1.0 mL / 291 K = 0.00344 mL/K
Now we can use the value of K to find the new volume at the final temperature:
Volume = K * Temperature
Volume = 0.00344 mL/K * 623 K ≈ 2.146 mL
Therefore, the new volume of the air bubble is approximately 2.146 mL when the bread bakes in the oven at 623 K (350°C).