# Calculus

Solve these indefinite and definite integrals.
[integration sign] 4j-5j^3 dj
I got 2j^2 - 5/4j^4... is this my final answer?

If j is the variable, for the indefinite integral you have to add a constant. For the definite integral, you have to put in the lower, upper limits.

j is an unusual variable symbol, I am use to j being sqrt -1

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asked by Alex

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