A stone propelled from a catapult with a speed of 50m/s attains a height of 100m.Calculate:(a)the time of flight?

time of fligt

t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s

A. time of flight

t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
B. The angle of projection
sinø=0.8944
Ø= sin–¹(0.8944)
Ø=63.4314654⁰
Ø ≈ 63.43⁰

C. Range
R=u²sin2ø/g
R=? u=50 , ø=63.4⁰, g= 10
= 50²*sin(2*63.4⁰)/10
=2500*sin(126.8⁰)/10
=250*0.8007
=200.2m
R≈200m

A. time of flight

t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
B. The angle of projection
sinø=0.8944
Ø= sin–¹(0.8944)
Ø=63.4314654⁰
Ø ≈ 63.43⁰

C. Range
R=u²sin2ø/g
R=? u=50 , ø=63.4⁰, g= 10
= 50²*sin(2*63.4⁰)/10
=2500*sin(126.8⁰)/10
=250*0.8007
=200.2m
R≈200m

T=8.945

Which Formular Will You Use To Get The Angle Of Projection?

A STONE IS PROPELLED FROM A CATAPULT WITH A SPEED OF 500MS ATTAINS THE HEIGHT OF 100M.CALCULATE,a:THE TIME OF FLIGHT,b:THE ANGLE OF PROJECTION,c:THE RANGE ATTAINED.

Tether=sin-1(Tg/2u)

am asking question a stone propelled from a catapult with a speed of 50 m/s attains a height of 100m calculate (a)the range attained

I THINK ANONYMOUS MAY BE CORRECT

I don't get why it is multiplied by 2