the first term of a linear sequence is 5,nd d common difference is -3 find the 15 term
Well, to find the 15th term of a linear sequence, we can use the formula:
nth term = first term + (n - 1) * common difference
In this case, the first term is 5, the common difference is -3, and we want to find the 15th term. Plugging those values into the formula, we get:
15th term = 5 + (15 - 1) * (-3)
= 5 + 14 * (-3)
= 5 + (-42)
= -37
So, the 15th term of this sequence is -37. It seems like this sequence is really going downhill!
To find the 15th term of a linear sequence with a first term of 5 and a common difference of -3, you can use the formula for the nth term of an arithmetic sequence:
Tn = a + (n - 1) * d
Where:
Tn = nth term
a = first term
n = term number
d = common difference
Plugging in the given values, we have:
T15 = 5 + (15 - 1) * -3
Simplifying the equation:
T15 = 5 + 14 * -3
T15 = 5 - 42
T15 = -37
Therefore, the 15th term of the sequence is -37.
To find the 15th term of a linear sequence, you can use the formula for the nth term of an arithmetic sequence:
nth term = first term + (n - 1) * common difference
In this case, the first term (a) is 5 and the common difference (d) is -3. Plugging these values into the formula, we get:
15th term = 5 + (15 - 1) * (-3)
Simplifying:
15th term = 5 + 14 * (-3)
= 5 - 42
= -37
Therefore, the 15th term of the given linear sequence is -37.