Mg(s) + 2HCl(aq) −> MgCl2(aq) + H2(g)
What mass of MgCl2 is produced?
Answer in units of g
second part
What mass of H2 is produced?
Answer in units of g
Your question isn't complete. No quantities.
To solve this problem, we first need to know the molar masses of all the compounds involved:
- Molar mass of Mg: 24.3 g/mol
- Molar mass of HCl: 36.5 g/mol (H: 1.01 g/mol, Cl: 35.5 g/mol)
- Molar mass of MgCl2: 95.2 g/mol (Mg: 24.3 g/mol, Cl: 35.5 g/mol x 2)
- Molar mass of H2: 2.02 g/mol (H: 1.01 g/mol x 2)
Now, let's calculate the mass of MgCl2 produced:
1. Determine the molar ratio between Mg and MgCl2:
- From the balanced chemical equation, we can see that the coefficient of Mg is 1, and the coefficient of MgCl2 is also 1. This means that 1 mole of Mg produces 1 mole of MgCl2.
2. Find the moles of Mg used:
- To find the number of moles of Mg, we divide the given mass of Mg by its molar mass:
Moles of Mg = Mass of Mg / Molar mass of Mg
3. Calculate the moles of MgCl2 produced:
- Since 1 mole of Mg produces 1 mole of MgCl2, the number of moles of MgCl2 will be equal to the number of moles of Mg.
4. Convert moles of MgCl2 to mass:
- Multiply the number of moles of MgCl2 by its molar mass to get the mass:
Mass of MgCl2 = Moles of MgCl2 * Molar mass of MgCl2
Now let's follow these steps to calculate the mass of MgCl2:
Given: The equation tells us we have 1 mole of Mg reacting with HCl, which means we have a 1:1 molar ratio between Mg and MgCl2.
1. Calculate the moles of Mg:
- The mass of Mg is not provided in the question, so let's assume we have 10 g of Mg as an example:
Moles of Mg = 10 g / 24.3 g/mol = 0.41 mol
2. Calculate the moles of MgCl2:
- Since the molar ratio is 1:1, the moles of MgCl2 will also be 0.41 mol.
3. Calculate the mass of MgCl2:
- Multiply the moles of MgCl2 by its molar mass:
Mass of MgCl2 = 0.41 mol * 95.2 g/mol = 39.03 g
Therefore, the mass of MgCl2 produced is approximately 39.03 g.
Now, let's calculate the mass of H2 produced:
1. Determine the molar ratio between HCl and H2:
- From the balanced chemical equation, we can see that the coefficient of HCl is 2, and the coefficient of H2 is also 1. This means that 2 moles of HCl produce 1 mole of H2.
2. Find the moles of HCl used:
- Since the balanced equation states that we have 2 moles of HCl, the number of moles of HCl would be twice the number of moles of Mg used.
3. Calculate the moles of H2 produced:
- Since 2 moles of HCl produce 1 mole of H2, the number of moles of H2 will be half the number of moles of HCl.
4. Convert moles of H2 to mass:
- Multiply the number of moles of H2 by its molar mass to get the mass:
Mass of H2 = Moles of H2 * Molar mass of H2
Let's calculate the mass of H2 using the given moles of Mg:
Given: We previously calculated that we have 0.41 mol of Mg, so we will use that value.
1. Calculate the moles of H2:
- Since the molar ratio is 2:1 (HCl to H2), the moles of H2 will be half the moles of HCl:
Moles of H2 = 0.41 mol / 2 = 0.205 mol
2. Calculate the mass of H2:
- Multiply the moles of H2 by its molar mass:
Mass of H2 = 0.205 mol * 2.02 g/mol = 0.4141 g
Therefore, the mass of H2 produced is approximately 0.4141 g.