3(n)-2(2n+2)=1/3(n+4)

help please,
show your work.

thank you!

If you meant

3(n)-2(2n+2)=1/3 * (n+4)

then just multiply by 3 and expand stuff out:

9n-6(2n+2)= (n+4)
9n-12n-12 = n + 4
-4n = 16
n = -4

If you meant

3(n)-2(2n+2)=1/(3(n+4))

then things get a bit more interesting and there is no real solution.

3n - 4n -4 = 1/3(n+4)

-n - 4 = 1/3 (n+4)
multiply all parts by 3

-3n -12 = n + 4
-4n = 16
n = -4

To solve the equation 3(n) - 2(2n + 2) = 1/3(n + 4), we will follow these steps:

Step 1: Distribute the terms inside the parentheses.
3n - 4n - 4 = 1/3n + 4/3

Step 2: Simplify the equation by combining like terms on both sides.
-n - 4 = 1/3n + 4/3

Step 3: Get rid of the fraction by multiplying every term of the equation by the common denominator, which is 3.
-3n - 12 = n + 4

Step 4: Isolate the variable (n) on one side of the equation by adding 3n to both sides.
-12 = 4n + 3n + 4

Step 5: Combine like terms again.
-12 = 7n + 4

Step 6: Move the constant term (4) to the other side of the equation by subtracting 4 from both sides.
-12 - 4 = 7n

Step 7: Simplify.
-16 = 7n

Step 8: Solve for n by dividing both sides by 7.
-16/7 = n

So, the solution to the equation is n = -16/7.