if a sample of iron(III) oxide contains 22.56g of iron, what is the mass of the sample?

do u just find the molar masses?

The molecular formula for iron(III) oxide is Fe2O3.

This means that 2 moles of Fe=1 mole of Fe2O3.

22.65g of Fe*( 1 mole of Fe/55.8 g)= moles of Fe

moles of Fe*(1 mole of Fe2O3/2 moles of Fe)*(159.69 Fe2O3 g/mol)= mass of the sample

To find the mass of the sample of iron(III) oxide, you need to consider the molar masses of both iron and oxygen, as well as their stoichiometric ratio in the compound.

1. Determine the molar mass of iron (Fe):
The atomic mass of iron (Fe) is approximately 55.85 g/mol.

2. Determine the molar mass of oxygen (O):
The atomic mass of oxygen (O) is approximately 16.00 g/mol.

3. Determine the stoichiometric ratio of iron and oxygen in iron(III) oxide (Fe2O3):
The chemical formula Fe2O3 indicates that there are two iron atoms and three oxygen atoms in one molecule of iron(III) oxide.

4. Calculate the molar mass of iron(III) oxide (Fe2O3):
Multiply the molar mass of iron by the number of iron atoms (2), and multiply the molar mass of oxygen by the number of oxygen atoms (3). Then, sum the two results.
Molar mass of Fe2O3 = (2 * Molar mass of Fe) + (3 * Molar mass of O)

5. Calculate the mass of the sample of iron(III) oxide:
Divide the given mass of iron (22.56 g) by the molar mass of iron (found in step 1). Then multiply the result by the molar mass of iron(III) oxide (calculated in step 4).
Mass of sample = (Mass of Fe / Molar mass of Fe) * Molar mass of Fe2O3

By following these steps, you can calculate the mass of the sample of iron(III) oxide.