the mass of 2.50 mol of a compound with the formula ECl4, in which E is a nonmetallic element, is 385g. what is the molar mass of Ecl4? what is the identity of E?
sorry, sent it twicee
molecular weight of Cl =35.4g
2.50 mol=385g of ECl4
This means that
1 mole of ECl4= (1/2.50)*385g= molecular weight of 1 mole of ECl4
molecular weight of 1 mole of ECl4-4(35.4g)= molar mass of E.
look up the identity in the periodic table.
thankks again!!1
To determine the molar mass of ECl4 and the identity of E, we need to use the given information.
First, we know that the mass of 2.50 mol of ECl4 is 385g. The molar mass is the mass of one mole of a substance, so we can calculate the molar mass using the formula:
Molar mass (g/mol) = Mass (g) / Amount (mol)
In this case, the amount is 2.50 mol, and the mass is 385g. Plugging in these values:
Molar mass = 385g / 2.50 mol
Simplifying:
Molar mass = 154 g/mol
Therefore, the molar mass of ECl4 is 154 g/mol.
Now, let's find the identity of E. We know that ECl4 is a compound in which E is a nonmetallic element. To determine the element using its molar mass, we need to use the periodic table.
Looking at the periodic table, we see that the element with a molar mass closest to 154 g/mol is Tin (Sn), which has a molar mass of approximately 118.71 g/mol.
Since tin does not match the molar mass of ECl4, we need to find another nonmetallic element that can form a compound with a molar mass of 154 g/mol.
From the periodic table, the nonmetallic element with a molar mass close to 154 g/mol is Selenium (Se), which has a molar mass of approximately 78.96 g/mol.
Therefore, the identity of E in ECl4 is Selenium (Se).
In conclusion, the molar mass of ECl4 is 154 g/mol, and the element E is Selenium (Se).