sam, pam, ken, and jen wrote each of their names on a slip of paper and placed them in a bowl.Sam was the first to randomly select a name from the bowl. What is the probability that he will select his own name? express answer as a fraction and a percent.(B)If sam selects Pam from the bowl, and Pam randomly selects after him, what is the probability the pam will select Sam's name?

Question

sam, pam, ken, and jen wrote each of their names on a slip of paper and placed them in a bowl.Sam was the first to randomly select a name from the bowl. What is the probability that he will select his own name? express answer as a fraction and a percent.(B)If sam selects Pam from the bowl, and Pam randomly selects after him, what is the probability the pam will select Sam's name?

Answer 1

So 4 names went into the bowl.

If Sam is the first person selecting then the chances of him pulling out his name are 1/4. 1/4 as a percent is 25%.

The second person selecting, Pam, now only has 3 names left in the bowl. Therefore, the chances that Pam will select Sam are now 1/3. 1/3 as a percent is 33.33(repeating)%.

Does that make sense?