Algebra Problem

State the value of the discriminant and the number of real solutions.

t^2+14t+49=0
The value of the discriminant is 0 and the equation has no real solution.

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  1. No

    If the discriminant is zero, then the quadratic factors to a perfect square, and there will be one real solution (actually two real but equal solutions)

    t^2+14t+49=0
    (t+7)^2 = 0
    t+7 = 0
    t = -7

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