in a circular road there is a fixed point from which two buses move in clockwise and anticlockwise. in every after 20 mins there is a bus moving in either direction.a man came to the point randomly and picked up the bus that came first.he came ten times in ten days and out of ten he got anticlockwise bus in 9 times.explain it using probability.why the percentage is 90% why not 50%

Question

in a circular road there is a fixed point from which two buses move in clockwise and anticlockwise. in every after 20 mins there is a bus moving in either direction.a man came to the point randomly and picked up the bus that came first.he came ten times in ten days and out of ten he got anticlockwise bus in 9 times.explain it using probability.why the percentage is 90% why not 50%

The only thing I can think of is it's the same as tossing a coin flipping heads 9 out of 10 times.

I'm assuming that in you're country, cars and buses drive on the LEFT side of the road. Therefore the bus driving on the inside, the counterclockwise-move bus, will be picked up more often.

Answer 1

To explain why the percentage is 90% and not 50%, let's break it down using probability.

First, let's consider the total number of possibilities for the bus selection. Each time the man comes to the point, there are two possible buses that could arrive first: the clockwise bus and the counterclockwise bus. Therefore, there are two possible outcomes for each of the ten times the man comes to the point, resulting in a total of 2^10 (2 raised to power 10) or 1024 possible outcomes.

Out of these 1024 possible outcomes, the man got the anticlockwise bus in 9 out of 10 times. To calculate the probability of this happening, we can use the formula:
Probability = (Number of favorable outcomes) / (Total number of possible outcomes)

In this case, the number of favorable outcomes is 9 (the times the man got the anticlockwise bus), and the total number of possible outcomes is 1024. So the probability of the man getting the anticlockwise bus is 9/1024, which can be simplified to approximately 0.0088 or 0.88%.

To express this probability as a percentage, we multiply the probability by 100. Therefore, the probability of the man getting the anticlockwise bus is approximately 0.88%.

So, the percentage of the man getting the anticlockwise bus is 0.88%, not 90%. It seems there might be some discrepancy in the information you provided. Please double-check the data to ensure accuracy.