find center and radius of circle
(x-6)^2+(y+9)^2=121
-(x-6)^2 -(x-6)^2
(y+9)^2=121-121-(x-6)^2
(y+9)^2=+/- �ã121-(x-6)^2
-9 -9
y=-9+/-�ã121-(x-6)^2
does anyone know is this the answer or do I go further???????????????????????
Your equation is already in the standard form of
(x-h)^2 + (y-k)^2 = r^2
where (h,k) is the centre and the radius is r
so for (x-6)^2+(y+9)^2=121
the centre is (6,-9) and the radius is 11
I have no clue what you were trying to do in your solution
.
Also this is the third student who has statements like your
-9 -9
in a sequential solution.
What is that supposed to mean?
Are you all from the same class?
I know Lori. We are suppose to show the number we left out or took away.
Where are they showing you that way?
Tell me the city or state or province, don't name the school
To find the center and radius of a circle, we need to rewrite the equation of the circle in the standard form: (x-a)^2 + (y-b)^2 = r^2, where (a,b) represents the coordinates of the center and r represents the radius of the circle.
In this case, the equation of the circle is given as (x-6)^2 + (y+9)^2 = 121. We need to rewrite this equation in the standard form.
Expanding the equation, we have:
(x-6)^2 + (y+9)^2 = 121
x^2 - 12x + 36 + y^2 + 18y + 81 = 121
x^2 + y^2 - 12x + 18y + 117 = 121
Rearranging the equation, we get:
x^2 + y^2 - 12x + 18y = 4
Now, we need to complete the square to express the equation in the standard form. We want to create perfect squares for the x and y terms:
x^2 - 12x + y^2 + 18y = 4
To complete the square for x, we take half the coefficient of x (-12/2 = -6), square it (-6^2 = 36), and add it to both sides of the equation:
x^2 - 12x + 36 + y^2 + 18y = 4 + 36
Similarly, for y, we take half the coefficient of y (18/2 = 9), square it (9^2 = 81), and add it to both sides of the equation:
x^2 - 12x + 36 + y^2 + 18y + 81 = 4 + 36 + 81
Simplifying the equation, we have:
(x - 6)^2 + (y + 9)^2 = 121
Comparing this with the standard form (x-a)^2 + (y-b)^2 = r^2, we can see that the center of the circle is (6, -9) and the radius is √121 = 11.