What is the ionic equation for (NH4)2CO3=2NH3+CO2+H2O

I would write this as

2NH4^+ + CO3^2-( ==> 2NH3(g) + CO2(g) + H2O(l) although some may want to see the SOLID (NH4)2CO3(s) displayed as is.

To determine the ionic equation for the reaction (NH4)2CO3 = 2NH3 + CO2 + H2O, we need to first write out the complete balanced equation.

The formula for ammonium carbonate is (NH4)2CO3. When it reacts, it gives 2 molecules of ammonia (NH3), 1 molecule of carbon dioxide (CO2), and 1 molecule of water (H2O).

The balanced equation for the reaction is:

(NH4)2CO3 → 2NH3 + CO2 + H2O

Now, let's break down each of the compounds into their ionic components.

(NH4)2CO3:
(NH4)+ + (CO3)2-

NH3:
NH4+ + OH-

CO2:
No ions, it remains as a molecular compound.

H2O:
H+ + OH-

Since CO2 remains as a molecular compound without dissociation, we don't need to consider its ions.

Now, let's write the ionic equation, only including the species that dissociate:

(NH4)2CO3 → 2NH4+ + (CO3)2-
2NH4+ + (CO3)2- → 2NH3 + H2O

Therefore, the ionic equation for the reaction (NH4)2CO3 = 2NH3 + CO2 + H2O is:

2NH4+ + (CO3)2- → 2NH3 + H2O

To determine the ionic equation for the given chemical reaction, we need to know the formulas and charges of the ions involved. Let's break down the compounds involved:

- (NH4)2CO3: This compound consists of ammonium ions (NH4+) and carbonate ions (CO3^2-).
- NH3: This is ammonia, which consists of ammonium ions (NH4+) and hydroxide ions (OH^-).
- CO2: This is carbon dioxide, which does not have any ionic form since it is a covalent molecule.
- H2O: This is water, which consists of hydrogen ions (H+) and hydroxide ions (OH^-).

Now, let's write the balanced ionic equation for the chemical reaction:

(NH4)2CO3 (aq) → 2NH3 (g) + CO2 (g) + H2O (l)

To balance the equation, we need to ensure there are an equal number of each type of atom on both sides of the equation. Here, we already have an equal number of each atom, so the equation is balanced as it is.

Therefore, the ionic equation for the reaction is:

(NH4)2CO3 (aq) → 2NH4+ (aq) + CO3^2- (aq)

Note that the CO2 and H2O in the balanced equation are not written in their ionic forms since they are covalent compounds and not dissociated in water.

i have no idea