How do you solve these types of math problems.
Directions: Solve each literal equation for the indicated variable.
A=1/2h(B+b) (For b) Area of a trapezoid
It is just a matter of algebraic manipulation.
A=(1/2)h(B+b)
Multiply both sides of the equation by 2/h.
B+b = 2A/h
b = (2A/h) - B
The formula
A
=
1
2
h
(
b
1
+
b
2
)
A=12h(b1+b2) gives the area,
A
A, of a trapezoid with parallel sides of length
b
1
b1 and
b
2
b2 and perpendicular height,
h
h .
How do I solve the literal equation for y
To solve this literal equation for the variable b, we want to isolate b on one side of the equation. Here's how we can do it:
1. Begin with the equation: A = (1/2)h(B + b)
2. Multiply both sides of the equation by 2/h to cancel out the coefficient of (1/2)h on the right side. This gives: (2A/h) = (B + b)
3. Subtract B from both sides of the equation to isolate the variable b. This gives: (2A/h) - B = b
So the solution to the literal equation A = (1/2)h(B + b) for the variable b is b = (2A/h) - B.