Two charges are arranged on the x axis so that there is a positive charge of 3.6 micro C at the orgin and a negative charge of .2.5 micro C located 2.5 centimeters to its right. to the nearest cetimeter, where on the x axis should a positive charge be placed so that the net force on it is zero?

Let the charge be to the right of the negative charge, and see if one can get a solution

F1 + F2=0
k3.6*q/x^2 - k2.5q/(x-2.5)^2=0
solve for x.

To find the position on the x-axis where a positive charge should be placed so that the net force on it is zero, we can use the principle of electrostatic forces.

The net force on a charge is given by Coulomb's law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

In this case, we have a positive charge of 3.6 μC at the origin and a negative charge of 2.5 μC located 2.5 centimeters to its right.

Let's assume that the positive charge is placed at a distance of x centimeters from the origin.

The force of attraction between the positive charge at the origin and the negative charge can be calculated using Coulomb's law:

F1 = (k * q1 * q2) / r1^2,

where F1 is the force between the positive and negative charges, k is the Coulomb's constant (approximately 9 × 10^9 N m^2/C^2), q1 and q2 are the charges, and r1 is the distance between them.

Similarly, the force of repulsion between the positive charges at the origin and the position x can be calculated:

F2 = (k * q1 * q3) / r2^2,

where F2 is the force between the positive charges, q3 is the charge at position x, and r2 is the distance between them.

Since we want the net force to be zero, we need to have F1 + F2 = 0.

Substituting the values we have:

(k * q1 * q2) / r1^2 + (k * q1 * q3) / r2^2 = 0.

Plugging in the given values: q1 = 3.6 μC, q2 = -2.5 μC, r1 = 2.5 cm, and k = 9 × 10^9 N m^2/C^2, we can solve for the position x.

Solving this equation will give us the value of x, which represents the position on the x-axis where a positive charge should be placed so that the net force on it is zero.