a boy travels 15 km due north,then goes 9 km due east,then 3km due south.how far is he from his starting point

find the distance the boat would have traveled if it had gone directly from point p to point t

He's 12 km north and 9 km east of his starting point.

Use the Pythagorean Theorem to find the hypotenuse of this right angle triangle.

how would i do that??

15

Jo guys i need help

Yes

To find the distance the boy is from his starting point, we can use the Pythagorean theorem.

First, let's break down the boy's journey into legs of his trip:

- The boy travels 15 km due north.
- Then, the boy goes 9 km due east.
- Finally, the boy travels 3 km due south.

To find the total distance from his starting point, we compute the distance between the starting point and the final point. This forms a right-angled triangle.

The distance traveled north and south contribute to the vertical side of the triangle, and the distance traveled east contributes to the horizontal side of the triangle.

Using the Pythagorean theorem, we can calculate the hypotenuse (the distance from the starting point). The formula is:

distance^2 = vertical distance^2 + horizontal distance^2

Substituting in the distances traveled:

distance^2 = (15 km - 3 km)^2 + 9 km^2
distance^2 = 12 km^2 + 9 km^2
distance^2 = 144 km^2 + 81 km^2
distance^2 = 225 km^2

Taking the square root of both sides, we find:

distance = √(225 km^2)
distance = 15 km

Therefore, the boy is 15 km away from his starting point.

Now, let's move on to the second part of your question about the boat's journey from point P to point T. Can you provide more information and coordinates for points P and T?