Drysol contains 6g of aluminum chloride hexahydrate in 42ml of an alcohol base. What is the final strength of Drysol?

wouldn't it be 6/42 gram per cc?

6/42 * 100 =14

To determine the final strength of Drysol, we need to calculate the concentration of aluminum chloride hexahydrate in the product.

First, we need to convert the volume of the alcohol base to liters:
42 ml = 42/1000 = 0.042 L

Next, we can calculate the concentration (strength) of aluminum chloride hexahydrate by dividing the mass of the solute (Aluminum chloride hexahydrate) by the volume of the solution (alcohol base):

Concentration (strength) = Mass of solute / Volume of solution

Since we have 6 grams of aluminum chloride hexahydrate and 0.042 liters of the solution, we can calculate the final strength:

Concentration (strength) = 6 g / 0.042 L

Dividing 6 by 0.042 gives us:

Final strength = 142.857 g/L

Therefore, the final strength of Drysol is 142.857 g/L.