Jana hit a golf ball with an initial velocity of 102 feet per second at an angle of 67° with the horizontal.
After 2 seconds, how far has the ball traveled horizontally?
Use this equation. X=t*v*cos(theta)
So 2*102*cos67=79.70915021
79.70915021
Well, Jana's golf ball must be on a real swing! Anyway, let's calculate how far it traveled horizontally.
To find the horizontal distance, we first need to find the horizontal component of the initial velocity. We can do this by multiplying the initial velocity by the cosine of the angle:
horizontal component = initial velocity × cosine(angle)
= 102 ft/s × cosine(67°)
Now, since we want to find the distance after 2 seconds, we can simply multiply the horizontal component by the time:
distance = horizontal component × time
= (102 ft/s × cosine(67°)) × 2 s
And there you go! Calculate the value and you'll have how far the ball traveled horizontally. Have fun with your math!
To find the horizontal distance traveled by the golf ball, we can use the equation for horizontal displacement:
Horizontal displacement (x) = Initial velocity (V₀) * Time (t) * cosine(angle)
Given:
Initial velocity (V₀) = 102 feet per second
Angle = 67°
Time (t) = 2 seconds
Step 1: Convert the angle from degrees to radians
Angle in radians = Angle in degrees * (π/180)
Angle in radians = 67° * (π/180) ≈ 1.17 radians
Step 2: Calculate the horizontal displacement
x = V₀ * t * cos(angle)
x = 102 * 2 * cos(1.17)
x ≈ 102 * 2 * 0.4409
x ≈ 90.18 feet
Therefore, after 2 seconds, the golf ball has traveled approximately 90.18 feet horizontally.
To find how far the golf ball has traveled horizontally after 2 seconds, we can use the equation for horizontal distance traveled:
Horizontal distance = initial velocity * time
Since we are given the initial velocity as 102 feet per second, and the time as 2 seconds, we can substitute these values into the equation:
Horizontal distance = 102 ft/s * 2 s
Horizontal distance = 204 feet
Therefore, after 2 seconds, the golf ball has traveled a horizontal distance of 204 feet.